Answer:
16.8 lb is the force on the brake pad of one wheel.
Step-by-step explanation:
Force applied on the piston =
![F_1=5.6 lb](https://img.qammunity.org/2020/formulas/physics/college/ewlwcwry9h44ltwv68r1uadsthfqabdbwr.png)
Area of the piston =
![A_1=0.6 inches^2](https://img.qammunity.org/2020/formulas/physics/college/v9ke5etk37mpt1u0adtzsfvwl4nhennh35.png)
Force applied on the brakes =
![F_2](https://img.qammunity.org/2020/formulas/physics/middle-school/7nsem8v8av15nh7hhnbf4zrjky07n8z6rk.png)
Area of the brakes =
![A_2=1.8 inches^2](https://img.qammunity.org/2020/formulas/physics/college/7ybw2lepvg7vooppiya6rxlwe7pryackjr.png)
Applying Pascal's law: 'For an incompressible fluid pressure at one surface is equal to the pressure at other surface'.
![(F_1)/(A_2)=(F_2)/(A_2)](https://img.qammunity.org/2020/formulas/physics/college/dn4y4chw20cfj1y5ox4rrvvkm3881f6h2b.png)
![F_2=(5.6 lb* 1.8 inhes^2)/(0.6 inches^2)=16.8 lb](https://img.qammunity.org/2020/formulas/physics/college/67ibm6bbadnf8tjb3ioqufzrj14vu7vjqb.png)
16.8 lb is the force on the brake pad of one wheel.