Question

What is ∛1728. Then multiplied by ∛14903

Answer 1

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

Solution:

Need to calculate
`\sqrt[3]{1728}` and then multiply the result by
`\sqrt[3]{14903}`

Let us first evaluate
`\sqrt[3]{1728}`

`\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 * 12 * 12}=12`

As need to multiply 12 by
`\sqrt[3]{14903}`

`\Rightarrow 12 * \sqrt[3]{14903}`

On solving
`\sqrt[3]{14903}`, we get

`\sqrt[3]{14903}=24.608`

`\Rightarrow 12 * \sqrt[3]{14903}=12 * 24.608=295.306`

Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.