Answer:
709
Explanation:
Sample size for an Interval estimate of population proportion is
n = (zα/2)^2 p (1-p) / E^2
given:
proportion, p = 0.21
margin of error, E = 0.03
Confidence level of 95%, that means the the siginficance level α is 1 – p
α = 1 – 0.95 = 0.05
Z(α /2) = Z(0.05/2) = Z (0.025)
Using a z table Z = 1.96
n = (zα/2)^2 p (1-p) / E^2
n = 1.96^2*0.21 (1-.21)/0.03^2
n = 708.13 ≈ 709