Question

A construction worker drops a hammer from a height of 50 feet. After how many seconds does the hammer land on the ground? Round your answer to the nearest hundredth.

Answer 1

7l07 sec

Explanation:

The pertinent equation is s(t) = -16t^2. We set this equal to zero to denote hammer hitting ground: -16t^2 = -50 ft. Solve for t^2 by dividing both sides by -16, obtaining

t^2 = 50 ft^2

The time required for the hammer to reach the ground is Sqrt(50 ft^2),

or 7.07 sec