Question

John drives to work each morning and the trip takes an average of µ = 38 minutes. The distribution of driving times is approximately normal with a standard deviation of σ = 5 minutes. For a randomly selected morning, what is the probability that John’s drive to work will take less than 35 minutes?​

Answer 1

The probability that John’s drive to work will take less than 35 minutes is 0.2743

Explanation:

Given :
`\mu = 38 \\\sigma = 5`

To Find :what is the probability that John’s drive to work will take less than 35 minutes?​

Solution:

`\mu = 38 \\\sigma = 5`

We are supposed to find P(x<35)

We will use z score

Formula:
`z=(x-\mu)/(\sigma)`

Substitute x = 35

`z=(35-38)/(5)`

z= −0.6

Refer the z table for p value

P(x<35)= 0.2743

Hence the probability that John’s drive to work will take less than 35 minutes is 0.2743