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How many moles of ZnCl, will be produced from 23.0 g of Zn, assuming CuCl, is available in excess?

User Rxxxx
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1 Answer

6 votes

Answer:

23 g of Zn will produce 0.352 mole of zinc chloride.

Step-by-step explanation:

Given data:

mass of Zn = 23 g

Moles of ZnCl = ?

Solution:

Chemical equation:

2Zn + CuCl₂ → 2ZnCl + Cu

Number of moles of Zn:

Number of moles of Zn = mass/ molar mass

Number of moles of Zn = 23 g / 65.38 g/mol

Number of moles of Zn = 0.352 mol

now we will compare the moles of ZnCl with Zn because it is limiting reactant.

Zn : ZnCl

2 : 2

0.352 : 0.352

So 23 g of Zn will produce 0.352 mole of zinc chloride.

User Jamie Niemasik
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