Answer:24 ways
Explanation:
Let
be the number of ways for choosing first prize.
Let
be the number of ways for choosing second prize.
Let
be the number of ways for choosing third prize.
The first prize can be decied in
ways beacuse there are
cyclists.
So,
![n_(1)=4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zqo53q2uc6a7bi611ltazg7khf1oibni67.png)
Since the first prize is already decided,the second prize can be decided in
ways.
So,
![n_(2)=3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ot0anz4c9w5tc7wgqjsgb4tu5eid95uogr.png)
Since the first two prizes are already decided,the third prize can be decided in
ways.
So,
![n_(3)=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ivk5y1ecscbj8s8gikjhk2gok8v85xt0ac.png)
Total number of ways is
![n_(1)* n_(2)* n_(3)=4* 3* 2=24 ways](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6hlofi1yrv6j72m64j6ajzb6088t1x75wm.png)