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A coconut fell from a tree. it fell a distance of 38m. how long was the coconut falling?

1 Answer

5 votes

Answer:

2.8 seconds

Step-by-step explanation:

Given:

Δy = 38 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

(38 m) = (0 m/s) t + ½ (9.8 m/s²) t²

t = 2.8 s

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