Question

An 8 g object displaces 50 mL of water. What is its specific gravity? 0.16 400 16 8.3

Answer 1

Option A

0.16

Explanation:

Specific gravity,
`SG=\frac {M_o}{M_w}` where M is mass of the object and v is mass of water with same volume as object. Since it's a ratio of masses, it's unitless

Taking density of water as 1 g/ml therefore the volume displaced of 50 ml is equivalent to 50 ml*1g/ml=50 g

Substituting 8 g for
`M_o` and 50 ml for
`M_w` we obtain

`SG=\frac {8g}{50g}=0.16`