Sam jimmy and andre shared a number of pennies in the ratio 8:5:3. same and andre recieved a total of 671 pennies. how many more pennies did jimmy recieve than andre. pls helppp…

Question

asked Sep 8, 2020 104k views

1 Answer

Mssm · Answer 1 · 2020-09-14T16:18:40+0000

Answer:

122

Explanation:

Sam,Jimmy and Andre shared a number of pennies in the ratio 8:5:3. Then

Sam has = 8x pennies

Jimmy has = 5x pennies

Andre has = 3x pennies.

Sam and Andre recieved a total of 671 pennies, so

$8x+3x=671\\ \\11x=671\\ \\x=61$

Hence,

Sam has
$=8\cdot 61=488$ pennies

Jimmy has
$=5\cdot 61=305$ pennies

Andre has
$=3\cdot 61=183$ pennies.

Jimmi recieved
305-183=122 more pennies than Andre.