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The coordinates of the vertices of △JKL are J(0, 2) , K(3, 1) , and L(1, −5) .

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The slope of JK¯¯¯¯¯ is , the slope of KL¯¯¯¯¯ is , and the slope of JL¯¯¯¯¯ is . △JKL a right triangle because .

The coordinates of the vertices of △JKL are J(0, 2) , K(3, 1) , and L(1, −5) . Drag-example-1
User Wade Huang
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5.8k points

2 Answers

3 votes

Answer: Look at the picture below for the answers :)

Explanation:

The coordinates of the vertices of △JKL are J(0, 2) , K(3, 1) , and L(1, −5) . Drag-example-1
User Budric
by
5.2k points
4 votes

Answer:

Part 1) The slope of JK is
m_J_K=-(1)/(3)

Part 2) The slope of KL is
m_K_L=3

Part 3) The slope of JL is
m_J_L=-7

Part 4) Triangle JKL is a right triangle because two of these slopes have a product of -1

Explanation:

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

The formula to calculate the slope between two points is equal to


m=(y2-y1)/(x2-x1)

we have


J(0, 2), K(3, 1),L(1, -5)

Part 1) Find the slope JK

we have


J(0, 2), K(3, 1)

substitute in the formula


m=(1-2)/(3-0)


m_J_K=-(1)/(3)

Part 2) Find the slope KL

we have


K(3, 1),L(1, -5)

substitute in the formula


m=(-5-1)/(1-3)


m_K_L=(-6)/(-2)


m_K_L=3

Part 3) Find the slope JL

we have


J(0, 2),L(1, -5)

substitute in the formula


m=(-5-2)/(1-0)


m_J_L=(-7)/(1)


m_J_L=-7

Part 4) Compare the slopes


m_J_K=-(1)/(3)


m_K_L=3


m_J_L=-7

we have that

JK and KL are perpendicular because their slopes are opposite reciprocal

The product of their slopes is equal to -1

therefore

Triangle JKL is a right triangle because two of these slopes have a product of -1

User Tet
by
5.0k points
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