Answer:k=4593.75
Step-by-step explanation:
Given
length of spring =20 cm
maximum compression in spring is x=8 cm
mass of mug m=300 gm
maximum height to which cup is needed to raise is h=5 m
By conserving Energy i.e. Elastic Potential Energy will be converted in to Potential energy of cup
![(kx^2)/(2)=mgh](https://img.qammunity.org/2020/formulas/physics/college/f3o6rdv3e1dgzx7jg1ycexovtpxgx0h6xx.png)
where
![k=spring\ constant](https://img.qammunity.org/2020/formulas/physics/college/akr345jn9j1riybk1s13etl23aq9uzlyoa.png)
![(k\cdot (0.08)^2)/(2)=0.3* 9.8* 5](https://img.qammunity.org/2020/formulas/physics/college/n46enppbpe7ya0t3t5v818tmjq4rvvja0t.png)
![k=(0.3* 9.8* 5* 2)/(64* 10^(-4))](https://img.qammunity.org/2020/formulas/physics/college/s4ymx4aemzp5cotljlvncwi834ggpzbeom.png)
so we should use a spring with spring constant k=4593.75 N/m