Question

Helppppo!!!

Grain is pored into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against eachother during the pouring process, one piece of grain picks up a charge of 6.0E-10C and another piece of grain picks up a charge of 2.3E-15C. What is the electric force between them if the pieces are 2 cm apart?

Answer 1

Electric force =
`3.15* 10^(-11)\textrm{ N}`.

Step-by-step explanation:

Given:

Charge on one grain,
`q_(1)=6* 10^(-10)\textrm{ C}`

Charge on second grain,
`q_(2)=2.3* 10^(-15)\textrm{ C}`

Distance between the two grains is,
`r=2\textrm{cm}=0.02\textrm{ m}`

Electric force acting between two charges
`q_(1)\textrm{ and }q_(2)` separated by a distance
`r` is:

`F_(e)=(kq_(1)q_(2))/(r^2)`

Where,
`k` is Coulomb's constant equal to
`9* 10^9\textrm{ }Nm^2/C^2`.

Now, plug in the given values and solve for
`F{e}`.

`F{e}=(9* 10^9* 6.0* 10^(-10)* 2.3* 10^(-15))/((0.02)^2)\\\\F_(elec)=3.15* 10^(-11)\textrm{ N}`

Therefore, the electric force between them is
`3.15* 10^(-11)\textrm{ N}`.