Question

Assume the average fuel flow rate at the peak torque speed (1500 rpm) is 15kg/hr for a sixcylinder four-stroke diesel engine under a certain condition. Each cylinder has one injector and each injector has 6 nozzle holes with a diameter of 200 micrometer. The discharge coefficient of the injector nozzle is 0.75. If the fuel injection pressure difference across the injector nozzle is 100MPa, what will be the fuel injection duration in Crank Angle degrees? Fuel density is 800 kg/m3 .

Answer 1

Q = 8.845 DEGREE

Step-by-step explanation:

given data:

combine Mass for 6 cylinder (M) =15 Kg/hr

mass of each cylinder (m) = 15/6 = 2.5 Kg/hr = 0.000694 Kg/ sec

Engine speed (N)= 1500rpm

Diameter of one nozzle hole ( d) = 200 micrometer = 0.0002 m

Discharge Coefficient (Cd) = 0.75

Pressure difference = 100 MPa

Density of fuel = 800 kg/m^3

velocity of fuel is
`v  = cd\sqrt{(2*P)/(p)}`

`v = 0.75 \sqrt{(2* 100* 10^6)/(800)} = 375 m/sec`

injected fuel volume (V) =Area of given Orifices × Fuel velocity × time of single injection × no of injection/sec

we know that p = m/ V

So
`V = (0.000694)/(800) =8.68*10^(-7) m3/sec`

putting these value in volume equation and solve for Discharge
`8.68* 10^(-7) = (((3.14)/(4))* 6*( .0002* .0002) *  375 *  ((Q)/(360)) * (30)/(750) * ((750)/(60))`

Q = 8.845 DEGREE