Question

For a spring oscillating in simple harmonic motion, at what point will the velocity of

the spring be greatest?

Answer 1

equilibrium position.

Step-by-step explanation:

In simple harmonic motion , velocity v(t) is given by,

v(t) = -ω A sin(ωt + φ)

where

ω = angular velocity of the corresponding circular motion

A = amplitude

t = time

φ = the initial angle of the corresponding circular motion when the motion begin.

v (t) get maximized when sin value is maximized , i.e. sin
`\alpha`=1

The particle has maximum speed when it passes through the equilibrium position.