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A 4 kg block is pulled with 5.6 N of force to the right. The block experiences 1.1 N of friction. What is the acceleration of the block?

1 Answer

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Step-by-step explanation:

Newton's second law:

∑F = ma

5.6 N − 1.1 N = (4 kg) a

4.5 N = (4 kg) a

a = 1.125 m/s² to the right

Round as needed.

User Raghu M U
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