Question

A 4 kg block is pulled with 5.6 N of force to the right. The block experiences 1.1 N of friction. What is the acceleration of the block?

Answer 1

The acceleration of the box is 1.125 m/s² towards right.

Step-by-step explanation:

Mass of the box,
`m=4` kg

Force acting towards right,
`F=5.6` N

Frictional force acting towards left,
`f=1.1` N

Let the acceleration be
`a` m/s².

Now, net force acting on the box towards right is given as:

`F_(net)=F-f=5.6-1.1=4.5\textrm{ N}`

From Newton's second law of motion,

`F_(net)=ma\\4.5=4a\\a=(4.5)/(4)=1.125\textrm{ }m/s^2`

Therefore, the acceleration of the box is 1.125 m/s² towards right.