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7 gifts are to be distributed among 10 children. how many distinct results are possible if no child is to receive more than 1 gift?

User Dale Kube
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2 Answers

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Final answer:

To find the number of distinct ways to distribute 7 gifts among 10 children, without any child receiving more than one gift, we use the combinations formula C(10, 7), yielding 120 distinct results.

Step-by-step explanation:

The question is asking how many distinct ways 7 gifts can be distributed among 10 children with the condition that no child receives more than one gift. This is a problem of calculating combinations without repetition, which is a part of combinatorial mathematics.

To solve this, we use the formula for combinations which is C(n, k) = n! / (k!(n - k)!). In this case, n is the total number of children (10) and k is the number of gifts (7). So the number of distinct results is C(10, 7).

Calculating this gives us:

10! / (7!(10 - 7)!) = 10! / (7!3!) = (10×9×8) / (3×2×1) = 120 distinct results.

User Metro
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This is the number of combinations of 7 in 10 which is the same as number of combinations of 3 in 10:
10C3 = 10*9*8 / 3*2*1

= 120
User Adris
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