Answer:
P ( percentage of days in which the circulation pass 1,801,000)
is equal to 100 % (almost)
P (percentage of days when the circulation drops below 1,611, 000)
is equal to 0 % (almost)
Explanation:
Let, in recent years, the daily circulation of the Wall Street Journal is given by the random variable X.
Then, according to the question,
X
Normal (2,276,207 , 70,940)
let,
= Z
then Z
Normal (0 , 1)
Now , for X = 1,801,000 , Z =
![(1,801,000- 2,276,207)/(70940)](https://img.qammunity.org/2020/formulas/mathematics/college/8piu4hcv888aw5grl07w74jgbtbax35c6y.png)
= -6.7 (approx)
Now, P ( percentage of days in which the circulation pass 1,801,000)
= P( Z > -6.7) = 100 % (almost)
So, P (percentage of days when the circulation drops below 1,611, 000)
= 0 % (almost) [ since, 1,801,000 > 1,611,000]