Answer:
One-fourth of the original gravitational force.
Step-by-step explanation:
The gravitational force between two objects of masses
is given as:
![F_(g)=(GmM)/(r^2)](https://img.qammunity.org/2020/formulas/physics/middle-school/fpf63z9knmptymgn9abdnjkzujc17xc2kk.png)
Where,
![G\rightarrow \textrm{gravitational constant}\\r\rightarrow \textrm{distance between the masses}](https://img.qammunity.org/2020/formulas/physics/middle-school/4phq0xn1zgo3kerr1kjp7xh8g3dn6yv8y5.png)
Therefore, the gravitational force is inversely proportional to the square of the distance between the masses.
Now, if the distance is doubled, then the force has to be reduced by a factor of one by four or gravitational force will one-fourth of the original.
Let us verify it.
If
, then new gravitational force is,
![F_(g,new)=(GmM)/((2r)^2)=(GmM)/(4r^2)=(1)/(4)(GmM)/(r^2)](https://img.qammunity.org/2020/formulas/physics/middle-school/umkekjd5bm798cdzgnzxlcfgcgbpywe8iw.png)
As seen above, new gravitational force is one-fourth of the original gravitational force between moon and Earth.