Question

If the charges attracting each other in the preceding problem have equal magnitudes,show that the magnitude of each charge is 2.8

Answer 1

The magnitude of each charge is
`2.82*10^(-6)\ C`

Step-by-step explanation:

Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.

We need to calculate the magnitude of each charge

Using formula of force

`F=(kq^2)/(r^2)`

Where, q = charge

r = separation

Put the value into the formula

`20=(9*10^(9)* q^2)/((6*10^(-2))^2)`

`q^2=((6* 10^(-2))^2*20)/(9*10^(9))`

`q=\sqrt{((6* 10^(-2))^2*20)/(9*10^(9))}`

`q=2.82*10^(-6)\ C`

Hence, The magnitude of each charge is
`2.82*10^(-6)\ C`