Question

Suppose that there are two types of tickets to a show: advance and same-day. Advance tickets cost $ 35 and same-day tickets cost $ 15 . For one performance, there were 65 tickets sold in all, and the total amount paid for them was $ 1675 . How many tickets of each type were sold?

Answer 1

Answer:35 advance tickets were sold

30 same day tickets were sold.

Explanation:

Let x represent the number of advance tickets sold.

Let y represent the number of same day tickets sold.

For one performance, there were 65 tickets sold in

This means that

x + y = 65

Advance tickets cost $ 35 and same-day tickets cost $ 15 and in all, and the total amount paid for them was $ 1675. It means that

35x + 15y = 1675 - - - - - - - - - - -1

Substituting x = 65 - y into equation 1. It becomes

35(65 - y) + 15y = 1675

2275 - 35y + 15y = 1675

- 35y + 15y = 1675 - 2275

- 20y = - 600

y = 600/20 = 30

x = 65 - y = 65 - 30

x = 35