Answer:
87.4 J
Step-by-step explanation:
The density of the gasoline is 0.70 g/mL, and the density of the ethanol is 0.79 g/mL. The heat combustions (the heat released in a combustion reaction) are 5,400 kJ/mol for gasoline, and 1,370 kJ/mol for ethanol.
For 3.5 L of E85, the volumes of gasoline and ethanol are:
Vgasoline = 0.15 * 3.5 = 0.525 L = 5.25x10⁻⁴ mL
Vethanol= 0.85 * 3.5 = 2.975 L = 2.975x10⁻³ mL
The mass of gasoline and ethanol presented in that sample of E85 is the volume multiplied by the density:
mgasoline = 5.25x10⁻⁴ * 0.70 = 3.675x10⁻⁴ g
methanol = 2.975x10⁻³ * 0.79 = 2.35025x10⁻³ g
The number of moles for each substance is it mass divided by its molar mass. The molar masses are 114 g/mol for gasoline, and 46 g/mol for ethanol:
ngasoline = 3.675x10⁻⁴/114 = 3.224x10⁻⁶ mol
nethanol = 2.35025x10⁻³ /46 = 5.109x10⁻⁵ mol
The energy released is the heat combustion multiplied by the number of moles, so:
Egasoline = 5,400 * 3.224x10⁻⁶ = 0.0174 kJ = 17.4 J
Eethanol = 1,370 * 5.109x10⁻⁵ = 0.07 kJ = 70 J
So, the energy released by the E85 is the sum of the energy released by ethanol and gasoline:
The energy released by E85 = 87.4 J