Question

Two objects with masses m and M are separated by a distance d. The magnitude of the gravitational force of attraction between the two blocks is given by F g = G M m d 2. If the separation d remains fixed and the masses of the objects are increased to the values 3m and 3M respectively, how does the magnitude of the gravitational force of attraction between the two objects change?

Answer 1

The new gravitational force of attraction is 9 times the original gravitational force

Step-by-step explanation:

G = Gravitational constant

d = Distance between the objects

m = Mass of one object

M = Mass of the other object

Universal gravitational force

`F=(GMm)/(d^2)`

When

m = 3 m

M = 3 M

`F_n=(G* 3M* 3m)/(d^2)\\\Rightarrow F_n=9(GMm)/(d^2)\\\Rightarrow F_n=9(GMm)/(d^2)\\\Rightarrow F_n=9F`

So, the new gravitational force of attraction is 9 times the original gravitational force