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A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 7.80 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration 1.60 times that due to gravity? (You do not need to enter any units.)

User Tauli
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1 Answer

7 votes

Answer:N=13.53 rpm

Step-by-step explanation:

Given

radius
r=7.80 m

Centripetal acceleration
a_c=1.6 g

and centripetal acceleration
a_c=\omega ^2r

where
\omega =angular\ velocity


1.6* 9.8=\omega ^2* 7.8


\omega ^2=2.0102


\omega =1.417 rad/s

and
\omega =(2\pi \cdot N)/(60)


1.417* 60=2\pi \cdot N


N=13.53 rpm

User Tim Edgar
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