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1.) You are the crew chief of the Algebra 2 formula racing team. Your current task is to

determine fuel consumption of both cars. Car A travel 2x + 2 miles and Car B travels 3x + 2 miles. Based upon tire wear (x), the cars will use x^2 + x gallons of fuel. What is the total
mileage for both cars?

a.) What is the mileage miles/gallons for each car?

Car A Car B


b.) What is the total mileage for both cars in simplified form?

User Bably
by
8.1k points

1 Answer

4 votes

Answer:

a). Mileage for carA=
(2)/(x) , and mileage for carB=
( 3x+2)/(x(x+1))

b).total mileage for both is similar to average of them=
((mileageA + mileageB))/(2)

=
(5x+4)/(2x(x+1))[tex]mil/gal

Explanation:

It is given that the distance traveled by car
A=2x+2=2(x+1)

And distance traveled by car
B= 3x+2

We know the mileage is mile/gallon,

a).So mileage of car
A= (distance traveled by car A)/(gallos of fuel used)


=(2x+2)/(x^2 +x)\\ =(2(x+1))/(x(x+1)) \\=(2)/(x)mil/gal

Similarly , the mileage for car
B= (distance traveled by car A)/(gallons of fuel used)


=(3x+2)/(x^2+x) \\=(3x+2)/(x(x+1))
mil/gal

b).total mileage for both is similar to average of them=
((mileageA + mileageB))/(2)


=(2x+2)/(x(x+1))+(3x+2)/(x(x+1))\\ =(2x+2+3x+2)/(x(x+1))\\=(5x+4)/(x(x+1))mil/gal

Now divide by 2 for total(average) mileage.


((5x+4)/(x(x+1)) )/(2)\\ =(5x+4)/(2x(x+1)) mil/gal.

Thus those are the answers.

User Steve Yost
by
7.4k points
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