Question

1.) You are the crew chief of the Algebra 2 formula racing team. Your current task is to

determine fuel consumption of both cars. Car A travel 2x + 2 miles and Car B travels 3x + 2 miles. Based upon tire wear (x), the cars will use x^2 + x gallons of fuel. What is the total
mileage for both cars?

a.) What is the mileage miles/gallons for each car?

Car A Car B


b.) What is the total mileage for both cars in simplified form?

Answer 1

a). Mileage for carA=
`(2)/(x)` , and mileage for carB=
`( 3x+2)/(x(x+1))`

b).total mileage for both is similar to average of them=
`((mileageA + mileageB))/(2)`

=
`(5x+4)/(2x(x+1))[tex]mil/gal`

Explanation:

It is given that the distance traveled by car
`A=2x+2=2(x+1)`

And distance traveled by car
`B= 3x+2`

We know the mileage is mile/gallon,

a).So mileage of car
`A= (distance traveled by car A)/(gallos of fuel used)`

`=(2x+2)/(x^2 +x)\\ =(2(x+1))/(x(x+1)) \\=(2)/(x)mil/gal`

Similarly , the mileage for car
`B= (distance traveled by car A)/(gallons of fuel used)`

`=(3x+2)/(x^2+x) \\=(3x+2)/(x(x+1))`
`mil/gal`

b).total mileage for both is similar to average of them=
`((mileageA + mileageB))/(2)`

`=(2x+2)/(x(x+1))+(3x+2)/(x(x+1))\\ =(2x+2+3x+2)/(x(x+1))\\=(5x+4)/(x(x+1))mil/gal`

Now divide by 2 for total(average) mileage.

`((5x+4)/(x(x+1)) )/(2)\\ =(5x+4)/(2x(x+1)) mil/gal`.

Thus those are the answers.