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What is the center of a circle represented by the equation (x-5)^2+(y+6)^2=4^2

1 Answer

3 votes

Answer:

(5, - 6)

Explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x - 5)² + (y + 6)² = 4² ← is in standard form

with (h, k) = (5, - 6) ← centre of circle

User Junaid Farooq
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