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What is the net force on this object: F norm = 20N F frict = 14N F app = 22N F grav = 20N?

User Ntombela
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2 Answers

2 votes

Answer:

8N i believe

Step-by-step explanation:

3 votes

Answer:

8N is the net force on the object.

Step-by-step explanation:

Given that,


\mathrm{F}_{\text {norm }}=20N is normal force acting upward (+20N)


F_{\text {frict }}=14N is frictional force which is opposite to the applied force (-14N)


\mathrm{F}_{\mathrm{app}}=22N is applied force which is applied on right side (+22N)


\mathrm{F}_{\mathrm{grav}}=20N is gravitational force acting downward (-20N)

We know that ,


\text { Fnet }=applied force
\left(\mathrm{F}_{\mathrm{app}}\right)+frictional force
\left(F_{\text {frict }}\right)+normal force
\left(\mathrm{F}_{\mathrm{norm}}\right)+gravitational force
\left(F_{\text {grav}}\right)


\mathrm{F}_{\mathrm{net}}=22+(-14)+ 20+(-20)


\mathrm{F}_{\mathrm{net}}=22-14+20-20


\mathrm{F}_{\mathrm{net}}=8 \mathrm{N}

Therefore the net force of the object be 8N.

User TheRealRonDez
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