Question

A theater group made appearances in two cities. The hotel charges before tax in the second city were $1500 lower than in the first. The tax on the hotel bill was 8% in the first city and 10% in the second. After the trip, the total tax paid on accommodation expenses was $435 . How much was the hotel bill in the first city before tax?

Answer 1

the first hotel cost $4350 before tax

Answer 2

The hotel bill in the first city before tax would be $ 650

Explanation:

Let x be the hotel charges ( in dollars ) before tax in the first city,

∵ Hotel charges before tax in the second city were $1500 lower than in the first.

So, the hotel charges in second city = ( x - 1500 ) dollars,

Now, percentage of tax in,

First city = 8%

Second city = 10%,

So, the total tax in both city = 8% of x + 10% of (x-1500)

`=(8x)/(100)+(10(x-1500))/(100)`

`=0.8x + 0.10(x-1500)`

According to the question,

`0.8x + 0.10(x-1500)=435`

`0.8x + 0.10x - 150 = 435`

`0.9x = 435 + 150`

`0.9x = 585`

`\implies x = (585)/(0.9)=650`

Hence, the hotel bill in the first city before tax would be $ 650.