Question

An object is thrown off a cliff with a horizontal speed of 16.8 m/s. After 5.60 seconds, the object hits the ground. Find the height of the cliff.

Answer 1

154 m

Step-by-step explanation:

Given (in the y direction):

v₀ = 0 m/s

a = 9.8 m/s²

t = 5.60 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (5.60 s) + ½ (9.8 m/s²) (5.60 s)²

Δy = 154 m