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Select the correct answer.

Laura is planning a party for her son. She has $50 dollars remaining in her budget and wants to provide one party favor per person to at least 10
guests. She found some miniature stuffed animals for $6.00 each and some toy trucks for $4.00 each.
Which system of inequalities represents this situation, where x is the number of stuffed animals and y is the number of toy trucks?

2 Answers

3 votes

Answer:

6x + 4y ≤ 50

x + y ≥ 10

Explanation:

$6 is the cost of stuffed animals $4 is the cost of toy trucks and the her maximum budget is $50 it would be 6x+4y is less then or equal to 50 and there is AT LEAST 10 people so the amounts which are x and y would be equal to or greater than 10.

User Wobbley
by
5.8k points
5 votes

Answer:


6x+4y\leq 50


x+y\geq 10

Explanation:


x represents the number of stuffed animals.


y represents the number of toy trucks.

Now, according to the problem, she found stuffed animals for $6.00 each and toy trucks for $4.00 each. Also, Laura has a restricted budget of $50. All these can be expressde as


6x+4y\leq 50

Also, the problem states that Laura wants to provide one partu favor per person to at least 10 people, that means


x+y\geq 10, because "at least" represents a minimum value, which is expressed with
\geq.

Therefore, the inequality system that models this situation is


6x+4y\leq 50


x+y\geq 10

User Grateful
by
6.5k points