Answer:
![15x^2+380x+2400](https://img.qammunity.org/2020/formulas/mathematics/college/sykg1lw8jwhcslwbwphmpc7j8wbna2mzqa.png)
The diagram is shown below for reference.
Explanation:
We are given the length and width of old pumpkin patch as
meters and
meters respectively.
It further says length is increased by
meters and width increased by
meters.
So the length of the new pumpkin patch would be
meters.
And the width would be
meters.
We know area of a rectangular shape
![=length * width](https://img.qammunity.org/2020/formulas/mathematics/college/izf0arru0nqmvm9xvjjmbaix04gs06dax8.png)
So, plugging the above values, we get the area of the new pumpkin patch as:
on rearranging.
Thus the function of the area of the new pumpkin patch would be:
![f(x) = 15x^2+380x+2400](https://img.qammunity.org/2020/formulas/mathematics/college/oadtme926mwg73seww0awxilkzz8kd4jok.png)