Question

A plane travels 25 km at an angle of 35 degrees to the ground, then changes direction and travels 515 km at an angle of 22 degrees to the ground. What is the magnitude and direction of the plane’s total displacement?

Answer 1

Magnitude is 539.39 Km

Direction is
`22.6^(\circ)`

Step-by-step explanation:

Using the cosine rule

X component is obtained by

x=25 cos 35 + 515 cos 22=497.9784862

Using the sine rule

Y component is obtained by

y=25 sin 35 + 515 sin 22=207.2618065

`Resultant=\sqrt{x^(2)+y^(2)}`

`Resultant=\sqrt{497.9784862 ^(2)+207.2618065 ^(2)}`

`Resultant=\sqrt {290940.0292 }`

`Resultant=539.3885697 \approx 539.39 Km`

Therefore, magnitude equals 539.39 Km

Direction

`\theta=tan^(1)\frac {y}{x}=tan^(1)(\frac {207.2618065}{497.9784862})=22.59738843^(\circ)\approx 22.6^(\circ)`