Question

The bond length in the HBr molecule is 1.41 Å. Calculate the dipole moments, in debyes, if the charges on the H and Br atoms were +1 and -1, respectively.

Answer 1

The Dipole moment is 6.77 Debyes.

Step-by-step explanation:

Given bond length of HBr molecule = 1.41 A°,

We also know charges on H and Br(+1 and -1 respectively)

Charge on H = (+1)
`*` (absolute charge of electron);

Charge on Br = (-1)
`*` (absolute charge of electron);

Since absolute charge on electron =
`1.602* 10^(-19)`;

Therefore charge on H =
`1.602* 10^(-19)` Coulomb;

charge on Br =
`-1.602*10^(-19)`

We know Dipole Moment = Charge
`*` Distance;

Here,

Distance = Bond Length = 1.41 A° = 1.41
`* 10^(-10)`;

and charge on atom =
`1.602* 10^(-19)` Coulomb;

Therefore,

Dipole Moment = Distance
`*` Charge

Dipole Moment =
`1.41*10^(-10) *1.602*10^(-19)`;

Dipole Moment =
`2.25882*10^(-29)` SI units.

The conversion factor of for SI units to Debye is 2.9989
`* 10^(29)`

Therefore,

Dipole Moment = 2.25882
`* 10^(-29)* 2.9985*10^(29)`

Dipole Moment = 6.77 Debye.