Answer:
The rate at which amount of photo increase after 6 days is 7.75
Explanation:
Given as :
The original amount of photo = 44
The final amount of photo = 44 + 25 = 69
Time period = 6 days
Let The rate = r
So, final value after n days = original value ×
![( 1+ (Rate)/(100))^(n)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/929wbph32hbx823v5turn805y54124c8m4.png)
Or, 69 = 44 ×
![( 1+ (r)/(100))^(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8bj1qzgyyz2sph3a0425w2d9k00tk7ig7y.png)
Or,
=
![( 1+ (r)/(100))^(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8bj1qzgyyz2sph3a0425w2d9k00tk7ig7y.png)
Or, 1.568 =
![( 1+ (r)/(100))^(6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8bj1qzgyyz2sph3a0425w2d9k00tk7ig7y.png)
Or,
=
![( 1+ (r)/(100))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/tyb2qgujt6hvjybwa0luscnpfg4hq4l9wo.png)
Or, ( 1.0775 - 1 ) × 100 = r
Or, 0.0775 × 100 = r
∴ r = 7.75
Hence The rate at which amount of photo increase after 6 days is 7.75 Answer