Question

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s ). If a particular disk is spun at 470.2 rad/s while it is being read, and then is allowed to come to rest over 0.569 seconds , what is the magnitude of the average angular acceleration of the disk?

Answer 1

826.36203 m/s²

Step-by-step explanation:

`\omega_f` = Final angular velocity = 470.2 rad/s

`\omega_i` = Final angular velocity = 0

`\alpha` = Angular acceleration

t = Time taken

Equation of rotational motion

`\omega_f=\omega_i+\alpha t\\\Rightarrow \alpha=(\omega_f-\omega_i)/(t)\\\Rightarrow \alpha=(0-470.2)/(0.569)\\\Rightarrow a=-826.36203\ m/s^2`

Magnitude of the average angular acceleration of the disk is 826.36203 m/s²