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The sample mean and standard deviation from a random sample of 32 observations from a normal population were computed as x¯=26 and s=9. Test whether there is enough evidence to infer at the 10% significance level that the population mean is greater than 23. Find the critical region. (e.g. t > 1 for a one-tailed test, or t < -1 or t > 1 for a two-tailed test.)

User Kenchilada
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1 Answer

4 votes

Answer:

There is enough evidence to infer at the 10% significance level that the population mean is greater than 23

Explanation:

Given that the sample mean is 26 and sample std dev = 9

i.e


\bar x = 26\\s=9\\n = 32\\se = (9)/(√(32) ) =1.591


H_0: \bar x = 23\\H_a: \bar x >23

(Right tailed test at 10% significance level)

Mean diff = 3

Test statistic t =
(3)/(1.591) \\=1.886

Critical region is t>1.310

df 31

p value = 0.034

Since p <0.10 reject null hypothesis

There is enough evidence to infer at the 10% significance level that the population mean is greater than 23

Critical region is in the enclosed file

The sample mean and standard deviation from a random sample of 32 observations from-example-1
User Himayan
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