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A 1500-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 40.0 mC/s at some instant in time.

Part A What will be the induced magnetic field strength 7.0 cm radially outward from the center of the plates?
Part B

What will be the value of the field strength after the capacitor is fully charged?

Express your answer with the appropriate units.

1 Answer

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Answer:


B= 1.14 X 10^(-7) Tesla

Step-by-step explanation:

B at point 7.0 cm radially outward is to find out?

Now for field strength in case of parallel plates in given as


B=(I\mu)/(2r\pi)


B=(4\pi X 10^(-7) (Tm)/(A)X40 X10^(-3) (C)/(s))/(2X0.07mX\pi)


B= 1.14 X 10^(-7) Tesla

For the second part as Capacitor is fully charged no more flow of current could take place hence

I= Current =o

so B = 0

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