Answer:
![B= 1.14 X 10^(-7) Tesla](https://img.qammunity.org/2020/formulas/physics/high-school/5gszl6v1fbd7hotuw98p6qau6t09vjxu7n.png)
Step-by-step explanation:
B at point 7.0 cm radially outward is to find out?
Now for field strength in case of parallel plates in given as
![B=(I\mu)/(2r\pi)](https://img.qammunity.org/2020/formulas/physics/high-school/uwdjmv7mvov1qmja5adzpqqvm2vg7lc8gm.png)
![B=(4\pi X 10^(-7) (Tm)/(A)X40 X10^(-3) (C)/(s))/(2X0.07mX\pi)](https://img.qammunity.org/2020/formulas/physics/high-school/lzvc8etfkjtfii3xrob33l4sv1cfj80po1.png)
![B= 1.14 X 10^(-7) Tesla](https://img.qammunity.org/2020/formulas/physics/high-school/5gszl6v1fbd7hotuw98p6qau6t09vjxu7n.png)
For the second part as Capacitor is fully charged no more flow of current could take place hence
I= Current =o
so B = 0