Question

2. At noon, a computer virus infects 1 byte of a computer's memory. Every minute

thereafter, the number of bytes infected doubles (is multiplied by two). At twelve

minutes after noon, a much worse computer virus infects 1 byte of another computer's

memory. Each minute thereafter, the number of bytes infected in that computer is

multiplied by eight. When will the number of bytes infected be the same in both

computers?



help!!!

Answer 1

At 12:18, eighteen minutes after noon, the number of bytes infected be the same in both computers.

Explanation:

1. Lets name PC1 the first computer and PC2 the second computer, so, at noon 1 byte of PC1 is infected with the virus, that is:

PC1

Hour Bytes infected

12:00 1

Then, every minute thereafter, the number of bytes is multiplied by two, that is:

PC1

Hour Bytes infected

12:01 2

12:02 4

12:03 8

12:04 16

12:05 32

12:06 64

12:07 128

12:08 256

12:09 512

12:10 1024

12:11 2048

12:12 4096

2. In the minute 12 after noon, 1 byte of PC2 is infected, meanwhile PC1 has 4096 bytes infected as shown above, that is:

PC1 PC2

Hour Bytes infected Bytes infected

12:12 4096 1

And each minute thereafter, the number of bytes infected in PC2 multiplied by eight, that is:

PC1 PC2

Hour Bytes infected Bytes infected

12:13 8192 8

12:14 16384 64

12:15 32768 512

12:16 65536 4096

12:17 131072 32768

12:18 262144 262144

Therefore, at 12:18, eighteen minutes after noon the number of bytes infected be the same in both computers.