Question

The rectangle shown has a perimeter of 50 cm and the given area. Its length is 4 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle

Answer 1

2 ( k + ( 2k +4)) = 50 cm is the required equation.

Width of rectangle = 7 cm, Length of rectangle = 18 cm

Explanation:

The perimeter of the rectangle = 50 cm

Le the width of the rectangle = k cm

⇒The length of the rectangle = (2k + 4) cm

Now, PERIMETER OF THE RECTANGLE = 2( LENGTH WIDTH)

⇒ 2 ( k + ( 2k +4)) = 50 cm

or, 2( 3k+ 4) = 50

⇒ 6k + 8 = 50

or, 6k = 50 - 8 = 42

or, k = 42/6 = 7

⇒ k = 7 cm

Hence, the width of the rectangle = k = 7 cm

and the length of the rectangle = (2k +4) = 2(7) + 4 = 18 cm