Question

Two acrobats flying through the air grab and hold onto each other in midair as part of a circus act. One acrobat has a mass of 60 kg and has a horizontal velocity of 5 m/s just before the grab. Another acrobat has a mass of 50 kg and has a horizontal velocity of -3 m/s just before the grab. Their horizontal velocity immediately after they grab onto each other is:

A. 1.4 m/s
B. 3.0 m/s
C. 0.6 m/s
D. 2.0 m/s
E. 4.1 m/s

Answer 1

Answer:1.4 m/s

Step-by-step explanation:

Given

mass of first acrobat
`m_1=60 kg`

velocity
`v_1=5 m/s`

mass of second acrobat
`m_2=50 kg`

velocity
`v_2=-3 m/s`

let us take v be the final velocity of two acrobats

`m_1\cdot v_1+m_2\cdot v_2=(m_1+m_2)v`

`60* 5-50* 3=(60+50)v`

`v=(300-150)/(110)`

`v=(15)/(11)=1.36 a\pprox 1.4 m/s`

Answer 2

Final velocity will be 1.4 m/sec

So option (a) is correct option

Step-by-step explanation:

We have given there are two acrobats

Mass of first acrobats
`m_1=60kg` and its velocity
`v_1=5m/sec`

Mass of second acrobats
`m_2=50kg` and its velocity
`v_2=-3m/sec`

Now from conservation of momentum we know that

`m_1v_1+m_2v_2=(m_1+m_2)v`

`60* 5+50* (-3)=(50+60)v`

`v=1.36=1.4m/sec`

So option (a) is correct option