Question

Solve the system of linear equations below.

2x + y = 5
x + y = 4
A.
x = 1, y = 3
B.
x = 1, y = 5
C.
x = 3, y = 1
D.
x = 9, y = -5

Answer 1

x = 1 , y = 3 thus: A is your Anser

Explanation:

Solve the following system:

{2 x + y = 5 | (equation 1)

x + y = 4 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + y = 5 | (equation 1)

0 x+y/2 = 3/2 | (equation 2)

Multiply equation 2 by 2:

{2 x + y = 5 | (equation 1)

0 x+y = 3 | (equation 2)

Subtract equation 2 from equation 1:

{2 x+0 y = 2 | (equation 1)

0 x+y = 3 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 1 | (equation 1)

0 x+y = 3 | (equation 2)

Collect results:

Answer: {x = 1 , y = 3

Answer 2

A. x=1, y=3

Explanation:

Hello, I can help you with this.

step 1

use elimination to solve this

Let (1) and (2)

(1)2x+y=5

(2)x+y=4

do (1)-(2) to eliminate y and solve for x

2x+y=5

-(x+y=4)

_______

(2x-x)+(y-y)=5-4

x=1

using x= 1 replace in (1) and isolate y

(1)2x+y=5

x=1

2(1)+y=5

2+y=5 (subtract 2 on each side)

2+y-2=5-2

y=3

so, the solution is

A. x=1, y=3

I really hope it helps, Have a good day.