Answer:
134.75935 seconds
Step-by-step explanation:
m = Amount of water = 240 mL
c = Specific heat of water = 4.2 J/mL °C
= Change in temperature =
![100-25=75](https://img.qammunity.org/2020/formulas/physics/college/nqash66blv5wfske7kdtq2mi8v7d9k4mk4.png)
t = Time taken
P = Power = 1100 W
E = Pt
Efficiency = 51 %
So, Energy = 0.51Pt
As energy is conserved
Q = 0
![\\\Rightarrow -mc\Delta T+E=0\\\Rightarrow -mc\Delta T+Pt=0\\\Rightarrow -240* 4.2(100-25)+0.51* 1100t=0\\\Rightarrow t=(240* 4.2(100-25))/(0.51* 1100)\\\Rightarrow t=134.75935\ s](https://img.qammunity.org/2020/formulas/physics/college/6g6gvzdtw6bngf8ftn1pycmnuze1nmdpii.png)
The it takes to raise the temperature is 134.75935 seconds