Option A
The values of x are 3.58 or 0.42
Solution:
Given, equation is
![-2(x-2)^(2)+5=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v784uvgtwthy1f9jkxbdz619zd89qivouc.png)
We have to solve for the x and choose from the options given,
Now, take the equation,
![\begin{array}{l}{\rightarrow-2(x-2)^(2)+5=0} \\\\ {\rightarrow-2(x-2)^(2)=-5}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/33ajb5sf44u9pe6jocfn2e54xgvfz1p1dt.png)
Negative sign cancels on both sides
![\begin{array}{l}{\rightarrow 2(x-2)^(2)=5} \\\\ {\rightarrow(x-2)^(2)=(5)/(2)}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zrg1arvcdrzludcfevfcsmrcbxjlalv1j6.png)
Taking square root on both sides, we get
![\begin{array}{l}{\rightarrow x-2=\sqrt{(5)/(2)}} \\\\ {\rightarrow x-2=\pm 1.58} \\\\ {\rightarrow x=2 \pm 1.58}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ow9ffsjwp3nq32g7o6tplh54v0taybq1n6.png)
![\begin{array}{l}{\rightarrow x=2+1.58 \text { or } 2-1.58} \\\\ {\rightarrow x=3.58 \text { or } 0.42}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pyrcyklgcdclthg8jua5z7ii1psalalnsc.png)
Hence, the values of x are 3.58 or 0.42, so option A is correct.