Question

A large natural gas storage tank is arranged so that the pressure is maintained at 2.20 atm. On a cold day in December when the temperature is -15°C, the volume of gas in the tank is 28,500ᶠᵗ³. What is the volume of the same quantity of gas on a warm July day when the temperature is 31°C?

Answer 1

V₂= 33581.4 ft³

Step-by-step explanation:

Given data:

Initial temperature = -15 °C (-15+273 = 258 k)

Initial volume = 28500 ft³

Final temperature = 31 °C (31+273 = 304)

Final volume = ?

Solution:

According to the Charles's law

Temperature and volume are directly related to each other.

V₁/T₁ = V₂/T₂

V₂ = V₁×T₂ /T₁

V₂ = 28500 ft³ × 304 k / 258 k

V₂ = 8664000 ft³.k/ 258 k

V₂= 33581.4 ft³