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Find the sum: (4x3−3x+2x3)+(2x−2x2+6x)

User Julieta
by
7.7k points

2 Answers

4 votes

9x+5

Explanation:

User Kurtis Streutker
by
8.3k points
1 vote

Answer:

The Sum of the Expression
(4x^3-3x+2x^3)+(2-2x^2+6x) is
(6x^3+2x^2+5x)

Explanation:

Given :


(4x^3-3x+2x^3)+(2x-2x^2+6x)

Now we will use the BODMAS method Which has a rule to use it and this rule states that if any equation has bracket, off, Divide ,Multiply , addition and subtraction signs then we will solve first Bracket then Off then Division then Multiplication then Addition and at last subtraction.

So,

Sum=
(4x^3-3x+2x^3)+(2x-2x^2+6x)

Sum=
(6x^3-3x)+(-2x^2+8x)

Sum=
(6x^3-3x-2x^2+8x)

Sum=
(6x^3-2x^2+5x)

Hence the Sum of the above Expression is
(6x^3-2x^2+5x)

User Skensell
by
8.1k points

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