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7 votes
Please find me the value of x​

Please find me the value of x​-example-1
User Humber
by
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2 Answers

15 votes
15 votes

Answer:

x = 60°

Explanation:

∠ ABO and ∠ CBO are a linear pair and sum to 180° , that is

∠ ABO + ∠ CBO = 180°

150° + ∠ CBO = 180° ( subtract 150° from both sides )

∠ CBO = 30°

∠ XYO and ∠ CBO are alternate angles and are congruent , so

∠ XYO = 30°

∠ XOY and ∠ COY are a linear pair and sum to 180° , then

∠ XOY + ∠ COY = 180°

∠ XOY + 90° = 180° ( subtract 90° from both sides )

∠ XOY = 90°

the sum of the 3 angles in Δ XOY = 180° , that is

x + 90° + 30° = 180°

x + 120° = 180° ( subtract 120° from both sides )

x = 60°

User Erik Z
by
3.2k points
13 votes
13 votes

Answer:

x = 60°

Explanation:

See picture below. When two parallel lines are cut by a transversal there are some special relationships.

Please find me the value of x​-example-1
User Vinze
by
3.2k points