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IXL problem help


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IXL problem help ……….-example-1
User Edric
by
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1 Answer

6 votes

Answer: 77

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Step-by-step explanation:

The triangles are congruent by the HL Theorem.

As such, the corresponding pieces angles EGH and EGF are congruent

angle EGH = angle EGF

7u-70 = 2u+35

7u-2u = 35+70

5u = 105

u = 105/5

u = 21

This leads to

  • angle EGH = 7u-70 = 7*21-70 = 147-70 = 77
  • angle EGF = 2u+35 = 2*21+35 = 42+35 = 77

Both angles mentioned are 77 degrees each to help confirm the answer.

User Mikenerone
by
4.5k points