Question

How long does it take an object thrown in the air with a velocity of 4.5m/s to reach its maximum height

Answer 1

0.46 s

Step-by-step explanation:

At the maximum height, the velocity is 0.

Given:

v₀ = 4.5 m/s

v = 0 m/s

a = -9.8 m/s²

Find: t

v = at + v₀

(0 m/s) = (-9.8 m/s²) t + (4.5 m/s)

t = 0.46 s